Hi,
As you're able to load items one by one, it might be easiest to dynamically
create a Objectarray, and the use java.util.Array to sort it. This is
available in from java 1.2 onwards.
so,
import java.util.Arrays;
import java.util.Comparator;
> NodeList PupilList = root.getElementsByTagName("pupil");
> int NumberPupils = PupilList.getLength();
Object[] myObject= new Object[ NumberPupils ];
Node PupilAlone;
> for (int i=0; i<NumberPupils; i++) {
> PupilAlone = PupilList.item(i);
myObjectArray[i] = PupilAlone;
}
// create your comparator here.
// you can find information on this in java.util.Comparator
Arrays.sort( myObjectArray, myComparator );
for(int i=0; i<NumberPupils; i++) {
> traversePupil( (PupilAlone) myObjectArray[i] );
}
do you see what I mean?
Software AG
<[EMAIL PROTECTED] To: "'[EMAIL PROTECTED]'"
<[EMAIL PROTECTED]>
lag.de> cc:
Subject: AW: How to order
alphabetically
21/11/2001
16:35
Please respond
to
xerces-j-user
Hi.
For XML the document order is important, so don't wonder why you get the
data this way.
If you want it different, there are many ways:
- Create your document ordered. XML preserves this order, and you can
retrieve the data ordered again.
This does not work if you can think of several ways of ordering.
- Use XSLT to change the ordering. There are quite simple statements that
can do what you need.
- Write your own DOM sorter. I cannot remember there is one in libraries
like Xalan or Xerces you can easily use.
Maybe (and hopefully) I'm wrong?
Hiran
> -----Urspr�ngliche Nachricht-----
> Von: Java Xerces Rule [mailto:[EMAIL PROTECTED]
> Gesendet: Mittwoch, 21. November 2001 17:31
> An: [EMAIL PROTECTED]
> Betreff: How to order alphabetically
>
>
> Hi all!
>
> I'm parsing an XML document:
> ------//-----------
> <table>
> <pupil>
> <name></name>
> <surname></surname>
> </pupil>
> ...
> </table>
> ----------//---------
>
> I would like to display Pupils' data, but ordering them
> alphabetically by the surname.
>
> I'm trying it by using:
> -----------//----------------
> NodeList PupilList = root.getElementsByTagName("pupil");
> int NumberPupils = PupilList.getLength();
> for (int i=0; i<NumberPupils; i++) {
> Node PupilAlone = PupilList.item(i);
> traversePupil(PupilAlone);
> ...
> ----------//--------------
>
> But they are ordered in the same way they are in the XML
> document.
>
> Any suggestion? Thank you very much.
> ______________________________________________________________
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