RE: question: XML Schema location

Puneet Narang 19 Mar 2002 10:41:20 -0000

Hi Demis,

The following code worked for me. (relativeXsdFilePath is relative path to my schema file on the file system and xml is my instance document)

I am using Xerces 2.0.0

I hope this helps you.

Puneet

try{

javax.xml.parsers.SAXParserFactory pf = javax.xml.parsers.SAXParserFactory.newInstance();

javax.xml.parsers.SAXParser sp = pf.newSAXParser();

org.xml.sax.XMLReader reader = XMLReaderFactory.createXMLReader("org.apache.xerces.parsers.SAXParser");

reader.setFeature("http://xml.org/sax/features/validation",true);

reader.setFeature("http://apache.org/xml/features/validation/schema",true);

reader.setProperty("http://apache.org/xml/properties/schema/external-noNamespaceSchemaLocation",relativeXsdFilePath);

reader.setErrorHandler(this);

org.xml.sax.InputSource is = new org.xml.sax.InputSource(new StringReader(xml));

reader.parse(is);

System.out.println("Parsing finished");

}catch(Exception e)

{

System.out.println("Exception " + e.getMessage());

e.printStackTrace();

}

-----Original Message-----
From: Demis Corvaglia [mailto:[EMAIL PROTECTED]
Sent: 19 March 2002 09:46
To: [EMAIL PROTECTED]
Subject: question: XML Schema location

Preliminary remarks: I'm a beginner!

I have tried to use XML Schema with Xerces 2.0.1 but I can't locate the xsd file on my file system.

I have read the XML Schema Limitations #usage, so this is the xsd (pattern.xsd):

<?xml version="1.0" encoding="utf-8"?>

<xs:schema xmlns:xs="http://www.w3.org/2001/XMLSchema">

....

</xs:schema>

and the xml file:

<?xml version="1.0" encoding="utf-8"?>

....

</PATTERN>

Is it enough? Pattern.xsd is in the same directory with the xml file. This is the validation feature activation:

        try {
            parser.setFeature("http://xml.org/sax/features/validation", true);
        } catch (SAXNotRecognizedException e) {
            System.err.println (e);
        } catch (SAXNotSupportedException e) {
            System.err.println (e);
        }

         // Turn Schema Validation on
        try {
            parser.setFeature("http://apache.org/xml/features/validation/schema", true);
        } catch (SAXNotRecognizedException e) {
            System.err.println (e);
        } catch (SAXNotSupportedException e) {
            System.err.println (e);
        }

When http://xml.org/sax/features/validation is true the error handler tell me that the element in the xml file must me declared.

When http://xml.org/sax/features/validation is false the parser work ok but the schema is ignored (infact if I delete it, for the parser is the same thing).

I have tried to use namespace, for example:

<document

  xmlns='http://my.com'

  xmlns:xsi='http://www.w3.org/2001/XMLSchema-instance'

  xsi:schemaLocation='http://my.com document.xsd'>

...

</document>

Probably I'm very silly but I can't understand: if the xsd is on my file system instead of http://my.com what have I to write?

After a lot of attempt, I have discovered the parser properties: http://apache.org/xml/properties/schema/external-schemaLocation and http://apache.org/xml/properties/schema/external-noNamespaceSchemaLocation. So:

        String id    = "http://apache.org/xml/properties/schema/external-noNamespaceSchemaLocation";
        String value = "pattern.xsd";
        try {
          parser.setProperty(id, value);
        }
        catch (SAXException e) {
          System.err.println("could not set parser properties " + e.getMessage());
        }

... but this produce an exception!! (in the DOM parser and in the SAX parses as well).

What can I do?

These are very stupid question I know, but there aren't tutorial or manual where to learn Xerces usage (or I can't find it).

Thank you.

Demis.

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