Anyone see anything wrong with this line from my shell script?
This is part of an AV script.

exitReject=[4 + $exit_Code]

Its supposed to add 4 to the exit code stored in $exit_Code which is usually
0 and store that total in exitReject so at the end of the script when  - >
exit $exitReject is excuted the script exits with that return code but for
some reason it always exits with the number 3.

Anyone got any ideas?




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Virus Database (VPS): 9/19/2003
Tested on: 9/22/2003 5:26:32 PM
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