I'll Give that a try thanks a lot for your help I'll let you know how it goes.
On Thu, Jul 12, 2012 at 7:07 PM, Piotr Sipika <[email protected]>wrote: > On 07/12/2012 09:53 AM, stuart shepherd wrote: > > Searching the web I've seen some examples in XSLT on how to > > do something like this, but I have never used XSLT. Does anyone know if > > there is a way to do this in XML. > > XSLT is your best bet. > > Here's a sample stylesheet which will: > - change the name of all elements named 'old' to 'new' > - change the name of all elements with an attribute named 'old' to 'new' > > ---- BEGIN stylesheet ---- > > <?xml version="1.0" standalone="yes"?> > <xsl:stylesheet version="1.0" > xmlns:xsl="http://www.w3.org/1999/XSL/Transform";> > <xsl:output method="xml"/> > > <!-- Template matches every node and attribute--> > <xsl:template match="node()|@*"> > > <xsl:choose> > <!-- if name of element is 'old' or element contains an attribute > named 'old', replace it with 'new' --> > <xsl:when test="@old or name(.)='old'"> > <xsl:variable name="old_node" select="node()"/> > <xsl:variable name="old_value" select="./text()"/> > <xsl:variable name="attributes" select="@*"/> > <xsl:variable name="children" select="./*"/> > > <!-- create a 'new' element with attributes and children from > the 'old' node, with its old value --> > <xsl:element name="new"> > <xsl:copy-of select="$attributes|$children"/> > <xsl:value-of select="$old_value"/> > </xsl:element> > </xsl:when> > > <!-- else, just copy the node/attributes --> > <xsl:otherwise> > <xsl:copy> > <xsl:apply-templates select="node()|@*"/> > </xsl:copy> > </xsl:otherwise> > </xsl:choose> > </xsl:template> > > </xsl:stylesheet> > > ---- END stylesheet ---- > > Sample XML: > <?xml version="1.0" standalone="yes"?> > <swap> > <old attr="attr1">This used to be inside the old node > <old_child1>This is old_child1</old_child1> > </old> > <foo attr="attr2">This is just a middle element...</foo> > <foo old="old attribute"/> > </swap> > > Output of stylesheet processing using xsltproc (libxml 20708, libxslt > 10126 and libexslt 815): > > $ xsltproc swap.xsl swap.xml > <?xml version="1.0"?> > <swap> > <new attr="attr1"><old_child1>This is old_child1</old_child1>This used > to be inside the old node > </new> > <foo attr="attr2">This is just a middle element...</foo> > <new old="old attribute"/> > </swap> > > > You can modify the attribute match criteria (@old) to actually evaluate > its contents ([@old='old_parent']), etc... > > Hope this helps. > > Piotr >
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