Question.. I'm using PHP 5.0.4 with the built-in libxslt-based xsl
extension. In PHP, I'm passing XSL parameters directly to the libxslt
processor like so:
$xslt_proc->setParameter('', 'param_test', "some test value");
My question is, is it *required* to declare this parameter in the XSL
stylesheet with:
<xsl:param name="param_test" />
What I have noticed is, the libxslt transformation is successful and
works the same whether I declare the parameter using xsl:param or not.
The following:
<xsl:value-of select="$param_test"/>
works fine without the xsl:param declaration, the libxslt processor
does not give an error, and the parameter is available for use in the
stylesheet.
Shouldn't the xsl:param declaration be required and cause a
transformation error if it's missing?
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