Hi,
I found the only reliable way to remove unwanted namespaces was to pass
the result set through a template....
e.g.
<xsl:template match="/">
<xsl:variable name="myUnDesiredOutput">
<xsl:apply-templates select="..."/>
</xsl:variable>
<xsl:apply-templates select="exsl:node-set($myUnDesiredOutput)"
mode="copy-no-namespace"/>
</xsl:template>
<xsl:template match="*" mode="copy-no-namespace">
<xsl:element name="{name()}"> <!-- This removes the namespace -->
<xsl:copy-of select="@*"/>
<xsl:apply-templates select="*|text()|comment()"
mode="copy-no-namespace"/>
</xsl:element>
</xsl:template>
<xsl:template match="text()|comment()" mode="copy-no-namespace">
<xsl:copy>
<xsl:copy-of select="@*"/>
<xsl:apply-templates select="*|text()|comment()"
mode="copy-no-namespace"/>
</xsl:copy>
</xsl:template>
Nick
-----Original Message-----
From: [EMAIL PROTECTED] [mailto:[EMAIL PROTECTED] On Behalf
Of Hans Guijt
Sent: 06 June 2007 18:21
To: [email protected]
Subject: Re: [xslt] Suppressing namespace attributes
Daniel Veillard wrote:
> the namespace prefix you define could be used by constructs outside
>of the structure and the XSLT processor has absolutely no way to guess
>whether this may impact the semantic of the output data. So as a rule
>XSLT-1.0 requires all namespaces in scope to be copied. Declare the
>namespace as an extension namespace that's the only way to avoid the
>copying.
I have tried adding extension-element-prefixes="ur" to my
<xsl:stylesheet> element, but unfortunately that seems to have the same
result as Brett's
suggestion: the xmlns:ur attribute moves from the <section> element to
the <para> element.
Combining the two solutions also fails to yield the desired result ;-)
Regards,
Hans Guijt
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