Hi Veljko, you can call predicate for testing. It will test if Vector3 is inside predicate or not. You can optionally use second parameter to specify "pad" = sphere radius.
pred = pack.inAlignedBox((0,0,0),(10,10,10)) s = sphere((0,0,0),1) for pos in ((.9,.9,.9),(1.1,1.1,1.1)): # whatever else.. s.state.pos = pos print pred(s.state.pos,s.shape.radius) cheers Jan 2015-02-12 15:01 GMT+01:00 velimier <question262...@answers.launchpad.net>: > New question #262000 on Yade: > https://answers.launchpad.net/yade/+question/262000 > > Hi, > is there method to determine whether sphere lies within given predicate? > > Thanks, > Veljko > > -- > You received this question notification because you are a member of > yade-users, which is an answer contact for Yade. > > _______________________________________________ > Mailing list: https://launchpad.net/~yade-users > Post to : yade-users@lists.launchpad.net > Unsubscribe : https://launchpad.net/~yade-users > More help : https://help.launchpad.net/ListHelp >
_______________________________________________ Mailing list: https://launchpad.net/~yade-users Post to : yade-users@lists.launchpad.net Unsubscribe : https://launchpad.net/~yade-users More help : https://help.launchpad.net/ListHelp
