what is zmq.zmq_version() on each?
-MinRK
> On Dec 29, 2013, at 0:01, Thomas Johnson <thomas.j.john...@gmail.com> wrote:
>
> Consider the following simple program:
> #----CUT HERE----
> #!/usr/bin/python
> import zmq
>
> context_push = zmq.Context(1)
> socket_push = context_push.socket(zmq.PUSH)
>
> context_pull = zmq.Context(1)
> socket_pull = context_pull.socket(zmq.PULL)
>
> socket_pull.bind("tcp://127.0.0.1:2000")
> socket_push.connect("tcp://127.0.0.1:2000")
>
> socket_push.send("Hello")
> message = socket_pull.recv()
> print "Got message: '%s'" % message
> #----CUT HERE----
>
>
> On machine A, as expected, it prints: Got message: 'Hello'
> On machine B, it prints: Got message: ''
>
> Separately from this program, Machine B also immediately raises a "Resource
> temporarily unavailable" if I create a PULL socket and do a (blocking)
> socket.recv() call. Strangely, it seems to hang if I do a
> socket.recv(flags=zmq.NOBLOCK), almost as if the flag was being flipped.
>
> Both A and B are Ubuntu precise, using pyzmq 14.0.1. B happens to have its
> native language set as Russian, if that matters.
>
> Any idea what is going on or what I'm doing wrong?
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