> Command "zpool get all poolName" does not provide any option to
> generate parsable output. The returned output contains 4 fields -
> name, property, value and source. These fields seems to be separated
> by spaces. I am wondering if it is safe to assume that there are no
> spaces in the field values. If this is the case, I can split the
> output across spaces.
For instance
#!/usr/bin/perl
# vim:ts=4:sw=4:si
my $pool = "mimedata";
open F,"zpool get all $pool|" || die "wtf?";
while (<F>) {
if (/^$pool\s+(\w+)\s+(\w+)/) {
my $key = $1;
my $value = $2;
print "$key => $value\n";
}
}
Vennlige hilsener / Best regards
roy
--
Roy Sigurd Karlsbakk
(+47) 97542685
r...@karlsbakk.net
http://blogg.karlsbakk.net/
--
I all pedagogikk er det essensielt at pensum presenteres intelligibelt. Det er
et elementært imperativ for alle pedagoger å unngå eksessiv anvendelse av
idiomer med fremmed opprinnelse. I de fleste tilfeller eksisterer adekvate og
relevante synonymer på norsk.
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