On Thu, Oct 4, 2012 at 9:14 AM, Richard Elling <richard.ell...@gmail.com> wrote:
> On Oct 4, 2012, at 8:58 AM, Jan Owoc <jso...@gmail.com> wrote:
> The return code for zpool is ambiguous. Do not rely upon it to determine
> if the pool is healthy. You should check the health property instead.
Huh. Learn something new everyday. You just simplified my "pool
health check" script immensely. Thank you!
pstatus=$( zpool get health storage | grep "health" | awk '{ print $3 }' )
if [ "${pstatus}" != "ONLINE" ]; then
Much simpler than the nested ifs and grep pipelines I was using before.
Not sure why I didn't see "health" in the list of pool properties all
the times I've read the zpool man page.
--
Freddie Cash
fjwc...@gmail.com
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