Maybe you can try simplifying your logic.
Why don't you avoid nested IFs till later, and keep to simple IFs.
If you want to check for $site_style not equal to 10 and also not equal to 9
then you can say
($site_style != 10 && $site_style != 9)
or even
!($site_style == 10 || $site_style == 9)
then later if you want to check for $site_style == 10
make a separate IF rather than use a elsif, just for ease of comprehension.
-Naintara
----- Original Message -----
From: "Jason Dulberg" <[EMAIL PROTECTED]>
To: "Rasmus Lerdorf" <[EMAIL PROTECTED]>
Cc: <[EMAIL PROTECTED]>
Sent: Thursday, October 04, 2001 11:12 AM
Subject: RE: [PHP] php in css not working with IF's
Thanks for sticking with me here and for your examples!!
So basically, I need to use AND instead of OR.
if (($site_style!=="10") && ($site_style!=="9") && ($site_style!=="8")) {
}
elseif ($site_style=="10") {
}
hrm... it didn't work.
Sorry for being such a dope about this.... :(
Jason
> Ok, you are clearly not following along here... ;)
>
> You have (let $site_style = A for brevity):
>
> if( A!=10 OR A!=9 OR A!=8 )
>
> When A=10 this becomes:
>
> if( 10!=10 OR 10!=9 OR 10!=8 )
> false true true
>
> if( false OR true OR true ) is the same as if (true)
>
> Seriously, try drawing the Venn diagram for your expression.
>
> Or try substituting common english.
>
> if Jason is not 21 or Jason is not 20 or Jason is no 19 let him into the
> cool club.
>
> Say Jason is 21, is he allowed in? Sure he is, because one of the
> conditions for getting into the cool club is that Jason is not 20. It
> doesn't matter that one of the other conditions says to not let Jason in.
> If the people writing the rules wanted to force all the conditions to
> apply they would have written:
>
> if Jason is not 21 AND Jason is not 20 AND Jason is not 19, let him into
> the cool club.
>
> -Rasmus
>
>
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