В Вс, 19/06/2022 в 14:40 +0300, andrey100100...@gmail.com пишет:
> В Вс, 19/06/2022 в 10:32 +0000, adr пишет:
> > On Sun, 19 Jun 2022, andrey100100...@gmail.com wrote:
> > > No way. All processes must run simultaneously.
> > > NFN limit cannot be bypassed.
> >
> > Yeah, that's why I said it was silly:
> > > > > The solution is obvious, cancel the process' handlers before
> > > > > it
> > > > > exits so we don't run out of space.
> > > >
> > > > This was really silly...
> >
> > The changes I'm testing are not for evading the limit, but for
> > making the handler managment more efficient and specially to avoid
> > the case when a process could remove another process' handler from
> > onnote[].
>
> Ok.
>
>
> More complete example with thread library:
>
> -------------------------------------------------------------
> #include <u.h>
> #include <libc.h>
> #include <thread.h>
>
> static int
> handler_alarm(void *, char *msg)
> {
> if(strstr(msg, "alarm")){
> return 1;
> }
>
> return 0;
> }
>
> static void
> proc_func(void *c)
> {
> Channel *chan = c;
>
> int fd, resp_len;
> char req[] = "request";
> char resp[512], *r = nil;
>
> if(threadnotify(handler_alarm, 1) == 0){
> fprint(1, "handler not registred\n");
> }
>
> alarm(2000);
> if((fd = dial("udp!185.157.221.201!5678", nil, nil, nil)) >=
> 0){
> alarm(0);
> alarm(2000);
> if(write(fd, req, strlen(req)) == strlen(req)){
> alarm(0);
> alarm(2000);
> if((resp_len = read(fd, resp, sizeof(resp)))
> 0){
> alarm(0);
> if((r = malloc(sizeof(resp))) ==
> nil){
> sysfatal("malloc error: %r");
> }
> memmove(r, resp, sizeof(resp));
> }
> }
> close(fd);
> }
>
+ alarm(0);
> send(chan, r);
> threadexits(nil);
> }
>
> int mainstacksize = 5242880;
>
> void
> threadmain(int argc, char *argv[])
> {
> Channel *chan = nil;
> char *data = nil;
> int nproc = 0;
>
> ARGBEGIN{
> case 'n':
> nproc = atoi(EARGF(threadexitsall(nil)));
> break;
> default:
> threadexitsall(nil);
> }ARGEND;
>
> if((chan = chancreate(sizeof(char *), 0)) == nil){
> sysfatal("channel error: %r");
> }
>
> for(int i = 0; i < nproc; i++){
> proccreate(proc_func, chan, 10240);
> }
>
> for(int i = 0; i < nproc; i++){
> if(data = recvp(chan)){
> free(data);
> }
> }
>
> if(nproc)
> fprint(1, "EXIT with nproc: %d\n", nproc);
>
> threadexitsall(nil);
> }
> -------------------------------------------------------------
>
> cpu% 6.out -n 33
> EXIT with nproc: 33
>
> with 34:
>
> cpu% 6.out -n 34
> handler not registred
>
> and stalled.
>
>
> So it is important for me that all processes respond.
> Such use, it seems to me, simplifies the program.
>
>
Regards,
Andrej
------------------------------------------
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