Try this:
import string
lines = ["1/12/2001,3,6,8,34,2", "1/13/2001,4,7,9,35,3"]
numbers_array = {}
for line in lines:
data = string.split(line, ",")
date = data[0]
numbers_array[date] = data[1:] # This is a slice of the list
Now you can access your information by:
print numbers_array["1/12/2001"] # prints the list
print numbers_array["1/12/2001"][0] # in your example, prints 3
Hope this helps!
Howard
http://howard.editthispage.com
At 11:06 AM 4/9/2001 -0700, David Ransier wrote:
>Hello experts. I'm very experienced with Perl, but new to Python. I'm trying
>to learn Python by converting some of my Perl scripts.
>
>I have a program that reads a file where each line is a date followed by
>some numbers. Like this:
> 1/12/2001,3,6,8,34,2
>
>This piece of code seems to work ok to organize the numbers as a list in a
>dictionary organized by data.
>
> for line in lines:
> data = string.split(line,',')
> date = data[0]
> numbers_ARRAY_X_date[date] =
>[data[1],data[2],data[3],data[4],data[5]]
>
>However, I would like to have a general solution that could add an arbitrary
>number of items to the dictionary list. I tried this, but the code fails:
>
> for line in lines:
> data = string.split(line,',')
> date = data[0]
> for n in range(1,6):
> numbers_ARRAY_X_date[date].append(data[n])
>
>The error message complains that append is not appropriate for the data
>type: numbers_ARRAY_X_date[date]
>
>Is there a way to coerce numbers_ARRAY_X_date[date] into a list? or is there
>another way to achieve this?
>
>
>Thanks,
>David R
>____________________________________________
>David Ransier
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>Fax: 503-416-3801 Suite 2200
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>
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