Try this:
numbers_ARRAY_X_date = {}
for line in lines:
data = string.split(line,',')
numbers_ARRAY_X_date[data[0]] = data[1:]
This will give you a dictionary item searchable by your date. Watch out
for duplicate dates unless you expect it to overwrite your dictionary item
values.
If you want it to be a list do it like this
numbers_ARRAY_X_date = []
for line in lines:
data = string.split(line,',')
numbers_ARRAY_X_date.append({data[0]: data[1:]})
This way you will have a list of dictionaries, and duplicate dates will not
get overwritten.
-Ryan
David Ransier
<[EMAIL PROTECTED]> To:
"Python-ActiveState (E-mail)"
Sent by:
<[EMAIL PROTECTED]>
[EMAIL PROTECTED] cc:
eState.com Subject: Help:
dictionary of lists
04/09/01 02:06 PM
Hello experts. I'm very experienced with Perl, but new to Python. I'm
trying
to learn Python by converting some of my Perl scripts.
I have a program that reads a file where each line is a date followed by
some numbers. Like this:
1/12/2001,3,6,8,34,2
This piece of code seems to work ok to organize the numbers as a list in a
dictionary organized by data.
for line in lines:
data = string.split(line,',')
date = data[0]
numbers_ARRAY_X_date[date] =
[data[1],data[2],data[3],data[4],data[5]]
However, I would like to have a general solution that could add an
arbitrary
number of items to the dictionary list. I tried this, but the code fails:
for line in lines:
data = string.split(line,',')
date = data[0]
for n in range(1,6):
numbers_ARRAY_X_date[date].append(data[n])
The error message complains that append is not appropriate for the data
type: numbers_ARRAY_X_date[date]
Is there a way to coerce numbers_ARRAY_X_date[date] into a list? or is
there
another way to achieve this?
Thanks,
David R
____________________________________________
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Fax: 503-416-3801 Suite 2200
Mobile: 360-921-5584 Portland, OR 97204
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