Hello,
I have just realized that the Python wrapper classes will probably not
compare as equal even if the underlying C++ class pointers point to the same
object. That's what probably is happening in the code below, because the 2nd
function uses a key that comes from a different wrapper around the same
object.
This must be a common problem with SWIG; does anyone know how to handle it
?
Thanks
----- Original Message -----
From: "Chris" <[EMAIL PROTECTED]>
To: <[EMAIL PROTECTED]>
Sent: Monday, August 16, 2004 1:24 PM
Subject: python keyerror problem ?
> Hello,
>
> I have a C++ class wrapped with swig. I add it as a key in a dictionary as
> follows:
>
> my_key = swigclass() # create class
> my_value = another_swigclass() # create 2nd class
> my_dict = {}
>
> my_dict[ my_key] = my_value
>
> If I print my_dict, it shows the expected key:value pair there. It
displays
> the wrapped values (i.e. a string with the pointer values and object type
> embedded )
>
> if I then access the value:
>
> my_dict[ my_key]
>
> it gives me the correct object (my_value) as expected
>
> Then, in another function, I try the same access on the same dictionary,
> (again after printing the dictionary contents to make sure it has
'my_key' )
>
> my_dict[ my_key]
>
> this generates a KeyError exception. I have no idea why, since the key is
> clearly valid and present in the dictionary.
>
> If I add a string key:value pair (eg. "test key" : "test value" ) to that
> same dictionary, and try to access "test key", that works fine .
>
> Can anyone help ?
> Thanks,
> Chris
>
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