Ben Goertzel wrote on Wednesday, October 15, 2008 7:57 PM
Is the "other node assembly" B fixed? So you're asking how many assemblies of size S will have less than O nodes overlap with some specific node assembly B with size S? [Ed Porter] Ben, If I understand your above quoted question correctly, the answer is "no.". I wanted to know, given N nodes, how many distinct node assemblies (each made of a different subset of size S from the nodes N) could you have, such that none of their populations would have more than O nodes overlapping with the population of any other of such node assembly, so the cross talk between activations in any one such group with any other such group could be guaranteed to be below a give level. This assumes that a given node can be used as part of multiple different cell assemblies, as do most discussions of cell assemblies. The answer to this question would provide a rough indication of the representational capacity of using node assemblies to represent concepts vs using separate individual node, for a given number of nodes. Some people claim the number of cell assemblies that can be created with say a billion nodes that can distinctly represent different concepts far exceeds the number of nodes. Clearly the number of possible subsets of say size 10K out of 1G nodes is a combinatorial number much larger than the number of particles in the observable universe, but I have never seen any showing of how many such subsets can be created that would have a sufficiently low degree of overlap with all other subsets as to support reliable representation for separate individual concepts. If the number such node subsets that can be created with sufficiently low overlap with any other node to clearly and reliably represent individual concepts is much, much larger than the number of nodes, it means cell assemblies might be extremely valuable to creating powerful AGI's. If not, not. Ed Porter ------------------------------------------- agi Archives: https://www.listbox.com/member/archive/303/=now RSS Feed: https://www.listbox.com/member/archive/rss/303/ Modify Your Subscription: https://www.listbox.com/member/?member_id=8660244&id_secret=117534816-b15a34 Powered by Listbox: http://www.listbox.com