Matt, >From a brief glace at your formula, it seems like it would be more likely to apply to a system in which each node is in only one cell assembly. This makes the math much more simple, but it fails to take advantage of the main advantages of cell assemblies, such as: possibly allowing many more concepts to be represented with a given number of nodes while allow more redundancy and, thus, reliability of representation when dealing with potentially unreliable neurons, and allowing the degree of retention of memories to gradually decline as the auto-associative weighting associated with the participation of individual nodes with different assemblies change by different amounts over time.
Also most of the neurobiological discussion I have read about cell assemblies indicates that often an individual neuron can be in many different cell assemblies as once. Ed Porter -----Original Message----- From: Matt Mahoney [mailto:[EMAIL PROTECTED] Sent: Wednesday, October 15, 2008 8:07 PM To: agi@v2.listbox.com Subject: Re: [agi] Who is smart enough to answer this question? --- On Wed, 10/15/08, Ed Porter <[EMAIL PROTECTED]> wrote: > Given N neural net nodes, what is the > number A of unique node assemblies > (i.e., separate subsets of N) of size > S that can have less than O > overlapping nodes, with the population > of any other such node assembly > similarly selected from the N nodes > to have the same size S and less than > the same O overlapping nodes with any > other such node assembly. A = (N-O)/(S-O). You let O nodes overlap with every assembly. Then you divide up the non-overlapping S-O nodes per assembly among the remaining N-O nodes. But that really isn't a useful answer. If a cell assembly is a group of neurons that tend to all fire at the same time, then a useful optimization is to model the whole assembly as a single neuron. -- Matt Mahoney, [EMAIL PROTECTED] ------------------------------------------- agi Archives: https://www.listbox.com/member/archive/303/=now RSS Feed: https://www.listbox.com/member/archive/rss/303/ Modify Your Subscription: https://www.listbox.com/member/?&; Powered by Listbox: http://www.listbox.com ------------------------------------------- agi Archives: https://www.listbox.com/member/archive/303/=now RSS Feed: https://www.listbox.com/member/archive/rss/303/ Modify Your Subscription: https://www.listbox.com/member/?member_id=8660244&id_secret=117534816-b15a34 Powered by Listbox: http://www.listbox.com
