Re: DIS: Proto: Complex scoring

[Alex Smith]

On Thu, 2008-11-06 at 16:08 -0700, Roger Hicks wrote:
> On Thu, Nov 6, 2008 at 15:51, Ed Murphy <[EMAIL PROTECTED]> wrote:
> > Proto-Proposal:  Complex scoring
> > (AI = 2, please)
> >
> A little help for those of us who haven't looked at imaginary numbers
> since high school. I recall that sqrt(-1) = i, but how do you
> calculate sqrt(-p)?
> 
It's i times sqrt(p): sqrt(ab) = sqrt(a*b) so sqrt(p*-1) = sqrt(-1) *
sqrt(p).
-- 
ais523