> can you explain that why the test you mentioned works? Consider ax+0xff changes the 0x100 bit iff the low-order byte of ax is not zero. ~ax always changes the 0x100 bit.
(~ax^(ax+0xff)) & 0x100 is zero iff both ~ax and ax+0xff have the same thing at the 0x100 position. You can extend this logic to the other bytes. --~--~---------~--~----~------------~-------~--~----~ You received this message because you are subscribed to the Google Groups "Algorithm Geeks" group. To post to this group, send email to algogeeks@googlegroups.com To unsubscribe from this group, send email to [EMAIL PROTECTED] For more options, visit this group at http://groups.google.com/group/algogeeks -~----------~----~----~----~------~----~------~--~---
