a^=b^=a^=b
On 3/9/06, hemu <[EMAIL PROTECTED]> wrote:
A different way ( or operators) but underlined logic is same as that of
XOR
A= ( A & ~ B ) | ( ~A & B)
B= ( A & ~ B ) | ( ~A & B)
A= ( A & ~ B ) | ( ~A & B)
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- [algogeeks] Re: swap hemu
- [algogeeks] Re: swap Michael Ageeb
