Thank you! I guess you understood the question now. Consider K and X >=0,
non-negative.

On Nov 24, 2007 10:41 PM, Nat Padmanabhan <[EMAIL PROTECTED]> wrote:

>
> 0 is not a positive number....your problem statement is wrong then
>
> On Nov 24, 2007 10:56 PM, Rupesh Bhochhi <[EMAIL PROTECTED]> wrote:
> > ok for instance, if K=2 then we will will have: 1.x1 + 2.x2 = 2.
> > Here the possible number of solution will be 2, namely: x1=2, x2=0  or
> x1=0,
> > x2=1. Please let me know if any confusion..
> >
> >
> > On Nov 24, 2007 9:50 PM, Nat Padmanabhan < [EMAIL PROTECTED]>
> wrote:
> > >
> > > I am not sure I understand the problem,
> > >
> > > x1=1, x2=1/2, x3=1/3....xk =  1/k is a trivial solution
> > >
> > >
> > >
> > >
> > > On Nov 24, 2007 10:41 PM, Rupesh Bhochhibhoya <[EMAIL PROTECTED]>
> wrote:
> > > >
> > > > Hello Geeks,
> > > >
> > > > Is there any efficient algorithm for finding number of possible
> > > > combination of X variables for the given value of K? where all X and
> K
> > > > are positive integers.
> > > > >
> > > >
> > >
> > >
> >
> >
> >
> > --
> > Rupesh Bhochhibhoya, [EMAIL PROTECTED]
> > Oklahoma State University
> > Stillwater, OK 74075
> >  >
> >
>
> >
>


-- 
Rupesh Bhochhibhoya, [EMAIL PROTECTED]
Oklahoma State University
Stillwater, OK 74075

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