ya boss rite.but according to asymptotic analysis the solutin shld be
O(n);rite??

On Wed, Mar 4, 2009 at 6:48 PM, Prakhar Jain <prakh...@gmail.com> wrote:

>
> see its log(n) + k where k<=the number of duplicates of the element
> being searched.
> For log(n), you can continue till your high comes on the element u
> desire and not low.
>
>
> On Wed, Mar 4, 2009 at 6:45 PM, sharad kumar <aryansmit3...@gmail.com>
> wrote:
> > "search() find any index and then iterates sequentially till the highest
> > index" how is this logn
> >
> > On Wed, Mar 4, 2009 at 6:44 PM, sharad kumar <aryansmit3...@gmail.com>
> > wrote:
> >>
> >> ya rite....
> >>
> >> On Wed, Mar 4, 2009 at 5:31 PM, Prunthaban <pruntha...@gmail.com>
> wrote:
> >>>
> >>> @sharad - Your solution is O(n) Miroslav's solution is O(logn).
> >>> And what are you doing with the 'j' variable in your solution? Why not
> >>> simply use a[i] == k then c = i. That is what eventually your solution
> >>> is doing and it is O(n).
> >>>
> >>>
> >>>
> >>> On Mar 4, 4:32 pm, sharad kumar <aryansmit3...@gmail.com> wrote:
> >>> > pls tell wats difference btwn increasing and non decresing sorted
> >>> > array.question clearly tells n sorted array.......
> >>> >
> >>> > On Wed, Mar 4, 2009 at 4:55 PM, Miroslav Balaz
> >>> > <gpsla...@googlemail.com>wrote:
> >>> >
> >>> > > of course, you cannot assume that array is in ascending order, it
> is
> >>> > > in
> >>> > > non-decreasing order however not in ascending
> >>> > > and you should swap order here :(a[mid+1] > key||mid==high)
> >>> >
> >>> > > 2009/3/4 Kapil <navka...@gmail.com>
> >>> >
> >>> > >> just fixing a bug
> >>> >
> >>> > >> what if you write bin_search as this
> >>> > >> //assumption array is in ascending order
> >>> > >> binsearch(high, low, key, a)
> >>> > >> begin
> >>> > >>  if low > high
> >>> > >>   return -1
> >>> > >>  mid = (high+low)/2
> >>> > >>  if a[mid] = key And (a[mid+1] > key||mid==high)
> >>> > >>    return mid
> >>> > >>  if a[mid] <= key
> >>> > >>   low = mid+1
> >>> > >>  else
> >>> > >>   high = mid - 1
> >>> > >>  return binsearch(high,low,key,a)
> >>> > >> end
> >>> >
> >>> > >> On Mar 4, 3:46 pm, Kapil <navka...@gmail.com> wrote:
> >>> > >> > what if you write bin_search as this
> >>> > >> > //assumption array is in ascending order
> >>> > >> > binsearch(high, low, key, a)
> >>> > >> > begin
> >>> > >> >  if low > high
> >>> > >> >    return -1
> >>> > >> >  mid = (high+low)/2
> >>> > >> >  if a[mid] = key And a[mid+1] > key
> >>> > >> >    return mid
> >>> > >> >  if a[mid] <= key
> >>> > >> >    low = mid+1
> >>> > >> >  else
> >>> > >> >    high = mid - 1
> >>> > >> >  return binsearch(high,low,key,a)
> >>> > >> > end
> >>>
> >>
> >
> >
> > >
> >
>
>
>
> --
> Prakhar
>
> >
>

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