ok.. great question
find the sum of the series , and the squares of the elements in the series
Let Sum = S
Sum of squares = P
now find the sum of the of all numbers from 1... (n+2) and their squares,
Let these be
A= (n+2)(n+3)/2 (for n = (n)(n+1)/2)
B= (n+2)(n+3)(2n+5)/6 (for n = (n)(n+1)(2n+1)/6)
therefore, v can deduce that
X + Y = A - S
X^2 + Y^2 = B - P
you got 2 equations, solve them
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