cant u use a string yaar.fruity gethu thaan

On Fri, Jul 31, 2009 at 9:57 PM, Vivek S <s.vivek.ra...@gmail.com> wrote:

> N! overflows...
> Try to write a program to find the value of 30!
> You don't have a variable that is large enough to store such a big
> number...
>
> 2009/7/31 sharad kumar <aryansmit3...@gmail.com>
>
>> check this out
>>
>> Let x and y be the missing number,
>>
>> Now equation 1 is : x + y = [n(n+1)/2] - S
>> equation 2 is: x * y = N! /P
>> solve both we get elements
>>
>> On Fri, Jul 31, 2009 at 8:27 PM, Devi G <devs...@gmail.com> wrote:
>>
>>> The logic is actually simple. Tot if we mark in some way an element when
>>> it's scanned, we can find the missing numbers in the second scannin.
>>>
>>> 3,5,1,2,9,10,8,6
>>>
>>> When for loop sees '3' it knows elt 3 is there. So multiplies the number
>>> at 3rd position by some arbitrary number. (* I've taken the arbitrary
>>> number to be n here but CORRECT ONE IS n+3 cos n will fail in some cases
>>> *)
>>>
>>> so, when it sees '5' multiplies the number at 5th position by n+3.
>>> It skips when the numbr is greater than n.
>>>
>>> n+3 = 11 here.
>>>
>>> So,after first loop,
>>> 33, 55, 11, 2 , 99, 110, 8, 66.
>>>
>>> So now, in the second scan, the indices of all elts that are divisible by
>>> n+3 are present in the array.
>>> elts at 4th and 7th positions are not divisible. hence missing numbers
>>> are 4 and 7.
>>>
>>>
>>>
>>>
>>>
>>
>>
>>
>
>
> --
> "Reduce, Reuse and Recycle"
> Regards,
> Vivek.S
>
> >
>

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