On Oct 13, 12:05 pm, Raghavendra Sharma <raghavendra.vel...@gmail.com>
wrote:
> For the first problem.
>
> All occurrence of a duplicate character in a word.
>
> void RemoveDuplicates(char *word) {
> int count[256] = {0, 0};
> char *p = word;
>
> while ( p ) {
This would be while(*p) {
> count[(int)(*p)] = 1;
> p++;
> }
>
> p = word;
> char *q = word;
>
> while ( q ) {
And This would be while(*q) {
> if ( count[*q] ) {
> *p = *q;
> count[*q] = 0;
> p++;
> q++;
> } else {
> q++;
> }
> }
> *p = '\0';
>
> }
>
> 2009/9/8 Matic Potočnik <maticpotoc...@gmail.com>
>
>
>
> > Hashing for words,
> > and a mapping to ASCII values for characters (make array of size
> > 256... if (A[(int)string[i]] == 0), an original char, A[(int)string[i]]
> > ++, else a duplicate char)
>
> > Go through string and delete duplicate chars and when you reach the
> > end of a word hash it and add it to output if it's original.
>
> > On Sep 8, 7:47 am, yash <yashpal.j...@gmail.com> wrote:
> > > wap a program in efficient manner to remove all occurrence of
> > > duplicate character in the word and all occurrence of duplicate word
> > > in the file.
>
> > > i break the problem in two section( this is my approach it may be
> > > better one )
>
> > > wap to remove all duplicate character in the word. (order is important)
> > > [i don't know which DS we use for this program your suggestion has
> > > highly appreciated]
> > > wap to remove all duplicate word in the file. (order is important)[we
> > > use tries to remove all duplicate word in the file]
>
> > > input in file
>
> > > we welcome your feedback, suggestions comment to make better your
> > > world
>
> > > After run the above compression algo output will be
>
> > > we welcom your fedback, sugtion coment to make betr world
>
> > > --
> > > Kind Regards
> > > ^_^
> > > Yashpal Jain
> > > Software Developer-IDC Risk
> > > PayPal - an ebay company
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