Vinod. Can you please mention steps for the O(n^2) solution that you
have thought of.

On Dec 2, 9:50 am, Vinoth Kumar <vinoth.ratna.ku...@gmail.com> wrote:
> No need for the code guys.
> Can u give me a  algo or pseudo code for this problem.
> I can think of a soln of O(n^2) but i need a algo for O(nlogn)
>
>
>
> On Wed, Dec 2, 2009 at 2:06 AM, NickLarsen <fodylar...@gmail.com> wrote:
> > That doesn't quite get it, try the input [ 7 3 4 2 1 6 5 8] and your
> > idea would miss [3 4 2]
>
> > On Dec 1, 10:10 am, sharad kumar <aryansmit3...@gmail.com> wrote:
> > > find out the subseq which are consecttive
> > > concatenate them at each level to get the entire set.
>
> > > On Tue, Dec 1, 2009 at 12:03 PM, Vinoth Kumar
> > > <vinoth.ratna.ku...@gmail.com>wrote:
>
> > > > Given an array A which holds a permutation of 1,2,...,n. A sub-block A
> > > > [i..j] of an array A
> > > > is called a valid block if all the numbers appearing in A[i..j] are
> > > > consecutive numbers (may not be in order.
>
> > > > Given an array A= [ 7 3 4 1 2 6 5 8]
> > > > the valid blocks are [3 4], [1,2], [6,5], [3 4 1 2], [3 4 1 2 6 5], [7
> > > > 3 4 1 2 6 5], [7 3 4 1 2 6 5 8]
>
> > > > Give an O( n log n) algorithm to count the number of valid blocks.
>
> > > > -- Vinod
>
> > > > --
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> --
> Cheers,
> Vinod

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