Condition:
Can we do it keeping the original lists intact ? ie without reversing it.
I mean , No recursion & no Reversing ... is it possible ?

@kumar :
15234 is represented as  1->5->2->3->4


On Wed, Jan 27, 2010 at 4:09 PM, saurabh gupta <sgup...@gmail.com> wrote:

> perhaps you mean,
> reverse each link list O(n+m).
> then sum each node with carryover maintained.
>
> On Wed, Jan 27, 2010 at 11:07 AM, Anurag Bhatia <abhati...@gmail.com>wrote:
>
>> Let us take an example -
>>
>> Num 1 = 123456
>> Num 2= 1234
>> Link-1->Link-2->Link-3->Link-4->Link5->Link6
>> Link-1->Link-2->Link-3->Link-4
>>
>> Add nodes into linkedlist 1 till either one of the list is not null.
>> Make sure you process the carry in each iteration.
>>
>>
>> --AB
>>
>>
>> On Tue, Jan 26, 2010 at 9:47 PM, Algoose Chase <harishp...@gmail.com>
>> wrote:
>> > conditions:
>> > NO extra memory (@ stack or Heap) at all. No recursion.
>> >
>> > Any body has got any hint about how to get this done ?
>> >
>> >
>> >
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