step 1 is n not m
which makes it O(3n)

On Wed, Jan 27, 2010 at 9:54 PM, saurabh gupta <sgup...@gmail.com> wrote:

> its not exponential
> time to find out m = m
> time to create list 3 = m
> time to create list 4 = n-m
> time to come up with proper added list (list 3 modification) = m
> time to merge list 3 and list 4 = n-m
>
> total time = 2n+m
>
> except step 1 all are reversals with approximately same constant and
> constant for step 1 is smaller
> so one can say
>
> O(2n+m)
>
>
> On Wed, Jan 27, 2010 at 5:26 PM, Anurag Bhatia <abhati...@gmail.com>wrote:
>
>> If that is the representation, then the lists have to be reversed.
>> Otherwise the time goes up exponentially.
>>
>> On Wed, Jan 27, 2010 at 5:19 PM, Algoose Chase <harishp...@gmail.com>
>> wrote:
>> > Condition:
>> > Can we do it keeping the original lists intact ? ie without reversing
>> it.
>> > I mean , No recursion & no Reversing ... is it possible ?
>> >
>> > @kumar :
>> > 15234 is represented as  1->5->2->3->4
>> >
>> > On Wed, Jan 27, 2010 at 4:09 PM, saurabh gupta <sgup...@gmail.com>
>> wrote:
>> >>
>> >> perhaps you mean,
>> >> reverse each link list O(n+m).
>> >> then sum each node with carryover maintained.
>> >>
>> >> On Wed, Jan 27, 2010 at 11:07 AM, Anurag Bhatia <abhati...@gmail.com>
>> >> wrote:
>> >>>
>> >>> Let us take an example -
>> >>>
>> >>> Num 1 = 123456
>> >>> Num 2= 1234
>> >>> Link-1->Link-2->Link-3->Link-4->Link5->Link6
>> >>> Link-1->Link-2->Link-3->Link-4
>> >>>
>> >>> Add nodes into linkedlist 1 till either one of the list is not null.
>> >>> Make sure you process the carry in each iteration.
>> >>>
>> >>>
>> >>> --AB
>> >>>
>> >>>
>> >>> On Tue, Jan 26, 2010 at 9:47 PM, Algoose Chase <harishp...@gmail.com>
>> >>> wrote:
>> >>> > conditions:
>> >>> > NO extra memory (@ stack or Heap) at all. No recursion.
>> >>> >
>> >>> > Any body has got any hint about how to get this done ?
>> >>> >
>> >>> >
>> >>> >
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