You can use a TRIE .. Structure can be something like this
struct trie
{
int count; // no of occurences
char *child[SIZE];
};
when ever u insert ( it will take just O(length) time) .. just increment
count by 1
For each query (also O(length) time) the no of occurrences of the word will
be count of the last character
Hope it helps
On Sat, Feb 27, 2010 at 5:35 PM, <piyushgoe...@gmail.com> wrote:
> Maintain a hash of word to freq. Keep adding words and incrementing their
> frequencies while reading the documents
>
>
> Pigol
>
>
> On Feb 27, 2010, at 5:10 PM, vijay <auvija...@gmail.com> wrote:
>
> You have to count the occurances of all words in a document. You are
>> given a method chat * GetNextWord, that returns the next word from the
>> document.
>> - Which datastructure can be userd to achieve this
>> -
>>
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