*Binary Indexed Trees* or *Segment Interval trees*.  building them also it
will take O(n log(n))
..i feel for a particular query it will be difficult less than O(n) .because
.u must know all the element.

On Wed, Mar 31, 2010 at 8:26 PM, Priyanka Chatterjee <dona.1...@gmail.com>wrote:

> The list of N integers is not sorted.
> The solution is asked for a particular query.
>
> @Abhijit Reddy: Can you elaborate more on* Binary Indexed Trees* or *Segment
> Interval trees*. May be you opted for the correct data structure. Please
> give the algorithm.
>
> @All: Doing a sorting for O(n logn) and then binary search for x1 and x2 in
> O(logn) will be less efficient than the simple solution of O(n). Think on
> the data structure that can optimize it.
> Is it possible in time complexity < O(n)?
>
>>
>>
>
>
> --
> Thanks & Regards,
> Priyanka Chatterjee
> Third Year Undergraduate Student,
> Computer Science & Engineering,
> National Institute Of Technology,Durgapur
> India
> http://priyanka-nit.blogspot.com/
>
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