#include<iostream>
#include<map>
#include<iterator>
using namespace std;
int main()
{
int arr[5]={12,3,4,3,3};
map<int,int>mp;
int i=0;
for(i=0;i<5;++i)
{
if(!(mp[arr[i]]))
mp[arr[i]]=i;
else
continue;
}
map<int,int>::iterator it;
for(it=mp.begin();it!=mp.end();++it)
cout<<it->second<<endl;
cin.sync();
cin.get();
return 0;
}
On Sun, Jun 6, 2010 at 3:14 PM, divya jain <sweetdivya....@gmail.com> wrote:
> @sharad
> while storing each element in hash by your approach u ll check if its
> already there in hash. so the complexity here will be O(n2). correct me if i
> m wrong. isnt there ny better algo..?
>
> On 6 June 2010 06:28, sharad kumar <aryansmit3...@gmail.com> wrote:
>
>> @dhivya:keep storing the first occurance element index in hash map and
>> then start insertin eleement ....based on index position
>>
>>
>> On Sun, Jun 6, 2010 at 12:31 AM, divya <sweetdivya....@gmail.com> wrote:
>>
>>> Given an array with some repeating numbers. Like 12,6,5,12,6
>>>
>>> output: 12,12,6,6,5
>>> 12 shud come before 6 since it is earlier in list. So cant use a
>>> dictionary.
>>>
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>>
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>> yezhu malai vaasa venkataramana Govinda Govinda
>>
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