@Anand :Your approach will turn out very crude if elements are something
like 1000, 2000
keeping an array i.e count[1000] is not feasible. I think souravsain's
approach is better.

On Mon, Jun 7, 2010 at 3:57 AM, Anand <anandut2...@gmail.com> wrote:

> Here is my approch which runs in O(n).
>
> http://codepad.org/d3pzYQtW
> <http://codepad.org/d3pzYQtW>
>
> On Sun, Jun 6, 2010 at 7:47 AM, divya jain <sweetdivya....@gmail.com>wrote:
>
>> output willl be 12 12 5 6 6
>>
>>
>> On 6 June 2010 18:27, souravsain <souravs...@gmail.com> wrote:
>>
>>> @divya: Does your problem require the output to be sorted also? What
>>> will be the output required if inout is 12,5,6,12,6? Will it be
>>> 12,12,6,6,5 or 12,12,5,6,6,?
>>>
>>> Sain
>>>
>>> On Jun 6, 12:01 am, divya <sweetdivya....@gmail.com> wrote:
>>> > Given an array with some repeating numbers. Like 12,6,5,12,6
>>> >
>>> > output: 12,12,6,6,5
>>> > 12 shud come before 6 since it is earlier in list. So cant use a
>>> > dictionary
>>>
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