how do u come to this formula T(n)=fib(n+2).. plz explain

On 7 June 2010 21:19, saurabh gupta <sgup...@gmail.com> wrote:

> it might be referring to no of sequences (say T(n) ) with no consecutive
> 1's
> for n = 3, ans would be 5 viz.
> 000, 001, 010, 100, 101
>
> T(n) =  fib(n+2)
> where fib = Fibonacci series
> which is interesting.
>
>
> On Sat, Jun 5, 2010 at 11:40 AM, Raj N <rajn...@gmail.com> wrote:
>
>> @sharad: What about 101 even it doesn't have two 1's in a row
>>
>>
>> On Sat, Jun 5, 2010 at 8:59 AM, sharad kumar <aryansmit3...@gmail.com>wrote:
>>
>>> @rajn.can it be subsequence doesnt have one's too.hence 000,001,010,100
>>> is required answer.
>>>
>>>
>>> On Sat, Jun 5, 2010 at 12:13 AM, Raj N <rajn...@gmail.com> wrote:
>>>
>>>> Hi,
>>>> I came across this question to find the number of sequences of n
>>>> binary digits that don't contain 2 1's in a row. I wanted to know what
>>>> exactly this means. Is it like if n=3 then compute all binary numbers
>>>> having 3 digits which don't have consecutive 1's 110, 011, 111 ??
>>>> If not help me understanding it.
>>>> Thanks!!
>>>>
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>>>
>>>
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>
>
>
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