Well
As we know for copying the string we can can copy it as a simple variable as
in case of address copying.
when u r doing names[3] = names[4] , it means u r trying to copy it directly
bt in the case of char *names[] , as it is the array of pointers so u can
copy the address from one pointer to another pointer....
Thanks
On Sat, Jun 12, 2010 at 9:12 PM, divya <sweetdivya....@gmail.com> wrote:
> #include<stdio.h>
>
> int main()
> { char names[][20]={
> "roshni",
> "manish",
> "sona",
> "baiju",
> "ritu"
> };
> int i;
> char *t;
> t=names[3];
> names[3]=names[4];
> names[4]=t;
> for(i=0;i<=4;i++)
> printf("%s",names[i]);
> printf("\n");
> return 0;
> }
>
> here i get l value required as error and if i replace char names[][2]
> with char *names[].. then there is no error nd the names[3] n names[4]
> interchange
> plzzzz explain why???
>
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--
Mahesh Giri
MCA Final Sem
JNU, New Delhi
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