sorry for the silly question i got rhe point..

@ rohit
compiler is doing rite..read mahesh's explanatn

On 13 June 2010 08:27, Rohit Saraf <rohit.kumar.sa...@gmail.com> wrote:

> This is very bad. Change your compiler if it compiles this stuff :)
>
> btw.. which compiler is it?
>
> Output for me :
> ro...@rohit-laptop:~/dump$ gcc c.c
> c.c: In function ‘main’:
> c.c:14: error: incompatible types when assigning to type ‘char[20]’ from
> type ‘char *’
> c.c:15: error: incompatible types when assigning to type ‘char[20]’ from
> type ‘char *’
>
> --------------------------------------------------
> Rohit Saraf
> Second Year Undergraduate,
> Dept. of Computer Science and Engineering
> IIT Bombay
> http://www.cse.iitb.ac.in/~rohitfeb14<http://www.cse.iitb.ac.in/%7Erohitfeb14>
>
>
>
> On Sun, Jun 13, 2010 at 8:13 AM, Mahesh_JNU <mahesh.jnumc...@gmail.com>wrote:
>
>> Well
>>
>> As we know for copying the string we can can copy it as a simple variable
>> as in case of address copying.
>> when u r doing names[3] = names[4] , it means u r trying to copy it
>> directly
>> bt in the case of  char *names[] , as it is the array of pointers so u can
>> copy the address from one pointer to another pointer....
>>
>> Thanks
>>
>>
>> On Sat, Jun 12, 2010 at 9:12 PM, divya <sweetdivya....@gmail.com> wrote:
>>
>>> #include<stdio.h>
>>>
>>> int main()
>>> { char names[][20]={
>>> "roshni",
>>> "manish",
>>> "sona",
>>> "baiju",
>>> "ritu"
>>> };
>>> int i;
>>> char *t;
>>> t=names[3];
>>> names[3]=names[4];
>>> names[4]=t;
>>> for(i=0;i<=4;i++)
>>> printf("%s",names[i]);
>>> printf("\n");
>>> return 0;
>>> }
>>>
>>> here i get l value required as error and if i replace char names[][2]
>>> with char *names[].. then there is no error nd the names[3] n names[4]
>>> interchange
>>> plzzzz explain why???
>>>
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>>
>>
>> --
>>   Mahesh Giri
>>  MCA Final Sem
>> JNU, New Delhi
>>
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