@ Raj: I have one doubt. The condition you gave for finding the height of
the tree satisfies on every node if tree is a doubly linked list. Correct me
if I missing out something



On Sat, Jun 26, 2010 at 12:25 PM, Raj N <rajn...@gmail.com> wrote:

> @jalaj: Use the same algorithm as finding the height of a normal tree (I
> hope you're familiar with it) . But to know that you've reached a leaf, you
> would normally use node->left or node->right ==NULL. But here in this case,
> the leaves form a doubly linked list, so the former condition can no longer
> be used and hence the condition becomes node==node->right->left which is
> nothing but node==node->next->previous in doubly linked list terminology.
>
> I hope this is clear.
>
> On Sun, Jun 27, 2010 at 12:48 AM, Raj N <rajn...@gmail.com> wrote:
>
>> @Algoose: Thanks for correcting it. Even I have made the same mistake as
>> Divya. It shud be node == node->right->left
>>
>>
>> On Sat, Jun 26, 2010 at 7:20 PM, Algoose Chase <harishp...@gmail.com>wrote:
>>
>>> If the parent Pointer is available we can use
>>>
>>> if( node->right->data > node->parent->data || node->right->data <
>>> node->data)  to identify the leaf nodes and use it as one of the recursion
>>> terminating condition in the original Height determining Algorithm.
>>>
>>> @Divya, I think u meant node != node->right->left
>>>
>>>
>>> On Sat, Jun 26, 2010 at 3:54 PM, divya jain <sweetdivya....@gmail.com>wrote:
>>>
>>>> yes..
>>>>
>>>> i got the solution traverse till node->right!=node->right->left... at
>>>> this point u ll get height.. rite?
>>>>
>>>>
>>>> On 26 June 2010 11:49, Raj N <rajn...@gmail.com> wrote:
>>>>
>>>>> @Divya: What will happen when say node->right when you reach the leaves
>>>>> ? Is it equivalent to node->next and node->left = = node->previous in the
>>>>> doubly linked list ?
>>>>>
>>>>>
>>>>> On Tue, Jun 22, 2010 at 4:44 PM, divya <sweetdivya....@gmail.com>wrote:
>>>>>
>>>>>> a bst is given whose leaf nodes having left as well as right pointers
>>>>>> not pointing to NULL. rather all the leaf nodes are forming a circular
>>>>>> doubly linked list. u have to calculate height of tree.
>>>>>>
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