@Anand: Agreed. But according to this problem only the leaves form the
doubly linked list

On Sun, Jun 27, 2010 at 10:41 AM, Anand <anandut2...@gmail.com> wrote:

> @ Raj: I have one doubt. The condition you gave for finding the height of
> the tree satisfies on every node if tree is a doubly linked list. Correct me
> if I missing out something
>
>
>
> On Sat, Jun 26, 2010 at 12:25 PM, Raj N <rajn...@gmail.com> wrote:
>
>> @jalaj: Use the same algorithm as finding the height of a normal tree (I
>> hope you're familiar with it) . But to know that you've reached a leaf, you
>> would normally use node->left or node->right ==NULL. But here in this case,
>> the leaves form a doubly linked list, so the former condition can no longer
>> be used and hence the condition becomes node==node->right->left which is
>> nothing but node==node->next->previous in doubly linked list terminology.
>>
>> I hope this is clear.
>>
>> On Sun, Jun 27, 2010 at 12:48 AM, Raj N <rajn...@gmail.com> wrote:
>>
>>> @Algoose: Thanks for correcting it. Even I have made the same mistake as
>>> Divya. It shud be node == node->right->left
>>>
>>>
>>> On Sat, Jun 26, 2010 at 7:20 PM, Algoose Chase <harishp...@gmail.com>wrote:
>>>
>>>> If the parent Pointer is available we can use
>>>>
>>>> if( node->right->data > node->parent->data || node->right->data <
>>>> node->data)  to identify the leaf nodes and use it as one of the recursion
>>>> terminating condition in the original Height determining Algorithm.
>>>>
>>>> @Divya, I think u meant node != node->right->left
>>>>
>>>>
>>>> On Sat, Jun 26, 2010 at 3:54 PM, divya jain 
>>>> <sweetdivya....@gmail.com>wrote:
>>>>
>>>>> yes..
>>>>>
>>>>> i got the solution traverse till node->right!=node->right->left... at
>>>>> this point u ll get height.. rite?
>>>>>
>>>>>
>>>>> On 26 June 2010 11:49, Raj N <rajn...@gmail.com> wrote:
>>>>>
>>>>>> @Divya: What will happen when say node->right when you reach the
>>>>>> leaves ? Is it equivalent to node->next and node->left = = 
>>>>>> node->previous in
>>>>>> the doubly linked list ?
>>>>>>
>>>>>>
>>>>>> On Tue, Jun 22, 2010 at 4:44 PM, divya <sweetdivya....@gmail.com>wrote:
>>>>>>
>>>>>>> a bst is given whose leaf nodes having left as well as right pointers
>>>>>>> not pointing to NULL. rather all the leaf nodes are forming a
>>>>>>> circular
>>>>>>> doubly linked list. u have to calculate height of tree.
>>>>>>>
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