On Sat, Jul 24, 2010 at 9:40 AM, tarak mehta <tarakmeht...@gmail.com> wrote:
> int arr[]={1,2,3,4};
> k=sizeof(arr)/sizeof(*arr);
> value of k=4;
>
> however
>
>
> void hell(int arr[]);
> main()
> {
> int arr[]={1,2,3,4};
> hell(arr);
> }
> void hell(int arr[])
> {
> printf("%d",sizeof(arr)/sizeof(*arr));
> }
>
>
> output of hell() is 1. why???
>
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> When array is passed as an argument, only a pointer to the first element of
the array is passed. Therefore the parameter int arr[] in void hell(int
arr[]) is just a pointer, hence the result .
I hope it answers your query.
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