void hell(int arr[]);
main()
{
int arr[]={1,2,3,4,5};
hell(arr);
}
void hell(int arr[])
{
printf("%d",sizeof(arr)/sizeof(*arr));
}
even this gives 1 !!
@manjunath ur idea seems correct..but could u plz elaborate a bit
On Sat, Jul 24, 2010 at 10:51 PM, Manjunath Manohar <
manjunath.n...@gmail.com> wrote:
>
>
> when arrays are passed as arguments to a function,the starting address of
> the array is passed like a pointer,
> thus sizeof(arr)=2..thus 2/2=1..this is the precise reason for always
> specifying the column length in the definition of function when functions
> have arrays as one of the arguments..
>
> Hope i made any sense.. :)
>
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