What if the number are not consecutive?

My approach-
Put the numbers in a hash till a collision occurs.

On Wed, Jul 28, 2010 at 9:21 PM, Apoorve Mohan <apoorvemo...@gmail.com>wrote:

> Solution :
>
> 1. Find Xor of numbers from 1 to n-1.
>
> 2. Find Xor of the numbers present in the array.
>
> 3. Xor the results from step 1 and 2 you will get the repeated number.
>
>
> On Wed, Jul 28, 2010 at 8:46 PM, akshay <akshayrastogi2...@gmail.com>wrote:
>
>> An array of unsorted numbers n is given with one no.repeated once ie
>> n-1 distinct nos to find duplicate no. in o(n) complexity
>>
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>
> Apoorve Mohan
>
>
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