This is a nice problem.  It looks like a trivial matroid, so a greedy
algorithm will work fine.  The obvious greedy algorithm is to work
left-to-right and incorporate elements into the sorted order one-by-
one.  In each case, you have 2 choices.  The first is to decrement
elements to the left by the amount needed to restore non-decreasing
order.  The second is to delete the new element.  The cost of each is
easy to calculate.  Pick the choice with least cost and continue.
This algorithm is O(n^2).  There may be a faster way to do it, but I
can't see one.

#include <stdio.h>

int make_nondecreasing(int *a, int n)
{
  int i, j, dec, dec_cost, total_cost;

  total_cost = 0;
  for (i = 0; i < n - 1; i++) {

    // If we find a decrease...
    if (a[i] > a[i + 1]) {

      // Find cost of decrementing all to the left.
      dec_cost = dec = a[i] - a[i + 1];
      for (j = i - 1; j >= 0; j--) {

        // Find decrement that would be needed.
        dec += a[j] - a[j + 1];

        // If no decement, we're done.
        if (dec <= 0)
          break;

        // Count cost of decrement.
        dec_cost += dec;
      }

      // Compare decrement cost with deletion cost.
      if (dec_cost < a[i + 1]) {

        // Decrement is cheaper.  Do it.
        for (j = i; j >= 0; j--) {
          if (a[j] > a[i + 1])
            a[j] = a[i + 1];
        }
        total_cost += dec_cost;
      }
      else {

        // Deletion is cheaper.  Do it.
        total_cost += a[i + 1];
        for (j = i + 1; j < n - 1; j++)
          a[j] = a[j + 1];
        --n;
      }
    }
  }
  return total_cost;
}

int main(void)
{
  int a[] = { 14, 15, 16, 13, 11, 18 };
  //int a[] = { 4, 3, 5, 6};
  //int a[] = { 10, 3, 11, 12 };
  int cost = make_nondecreasing(a, sizeof a / sizeof a[0]);
  printf("cost=%d\n", cost);
  return 0;
}

On Aug 27, 12:15 pm, jagadish <jagadish1...@gmail.com> wrote:
> You are given an array of positive integers. Convert it to a sorted
> array with minimum cost. Only valid operation are
> 1) Decrement -> cost = 1
> 2) Delete an element completely from the array -> cost = value of
> element
>
> For example:
> 4,3,5,6, -> cost 1
> 10,3,11,12 -> cost 3

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