1)get the numbers
2)Sort the numbers
3)traverse from first number
4)if (a[i]==a[i+1]-1 )
{
count++;
sum+=(a[i]+a[i+1])
i++;
}
5)if (sum>max)
{
end=count;
max=sum;
}
6)print down to "count" no of elements from a[end]
will this algorithm wok?correct me if i am wrong.....
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