@coolfrog, What I meant by remained is
Considering your case of A,B,C,D and B is the celebrity, The sequence is First A,B ask the question to A, then remained=B Then B,C ask the question to B, then remained=B Then B,D ask the question to B, then remained= B Then ask A,C,D whether they know B Then ask B whether they know A,C,D So, that's how I said 3(n-1) questions... Correct me if I am wrong On Thu, Sep 23, 2010 at 8:32 PM, coolfrog$ <dixit.coolfrog.div...@gmail.com>wrote: > > @kartheek > i am getting. this prudent approach.... > but what is "add what remained to the remainder." > suppose u have A,B,C,D and B is celebrity ... > > if( A knows B) > { A is not celb. > if( B knows C){} > else{ C is not celb. > if (C knows B ) > { if( D knows B) > { D is not celb. > only B remain... hence it celeb... > /* suppose if u have A,B,C,D,E > and B is celeb. > then again if (E knows B) > { E is not > celb.... > only B > remain... hence it celeb... > } > */ > } > } > } > } > look in every if condition we are Asking Sequentially to A > ,B,C,D,E....... > can these be correct solution .... > correct me plz... if wrong...... > On Thu, Sep 23, 2010 at 12:56 AM, kartheek muthyala < > kartheek0...@gmail.com> wrote: > >> Take 2 persons, suppose say A and B >> ask one of them the question about other >> if A Knows B, then A cannot be the celebrity, >> if A does not know B, then B cannot be the celebrity. >> add what remained to the remainder. >> >> repeat this process for the remaining n-1 until one or none remained. >> >> Then if it is none then there is no celebrity. >> If there is one ask the question whether this person is known by remaining >> n-1 and this person does n't know the remaining n-1. So a total of 3(n-1) >> questions is used to determine the celeb. >> >> Time complexity is O(n). >> >> Repeat this for the remaining n-1 persons, if the remainder contain one >> then >> >> >> On Wed, Sep 22, 2010 at 9:37 PM, Divesh Dixit < >> dixit.coolfrog.div...@gmail.com> wrote: >> >>> Among n people, a celebrity is defined as someone who is known to >>> everyone, but who knows no >>> one. Design and analyze to identify the celebrity, if one exists, by >>> asking only questions of the >>> following form: "Excuse me, do you know person x?" You will get a >>> binary answer for each such >>> question asked. Find the celebrity by asking only O(n) questions. >>> >>> -- >>> You received this message because you are subscribed to the Google Groups >>> "Algorithm Geeks" group. >>> To post to this group, send email to algoge...@googlegroups.com. >>> To unsubscribe from this group, send email to >>> algogeeks+unsubscr...@googlegroups.com<algogeeks%2bunsubscr...@googlegroups.com> >>> . >>> For more options, visit this group at >>> http://groups.google.com/group/algogeeks?hl=en. >>> >>> >> -- >> You received this message because you are subscribed to the Google Groups >> "Algorithm Geeks" group. >> To post to this group, send email to algoge...@googlegroups.com. >> To unsubscribe from this group, send email to >> algogeeks+unsubscr...@googlegroups.com<algogeeks%2bunsubscr...@googlegroups.com> >> . >> For more options, visit this group at >> http://groups.google.com/group/algogeeks?hl=en. >> > > -- > You received this message because you are subscribed to the Google Groups > "Algorithm Geeks" group. > To post to this group, send email to algoge...@googlegroups.com. > To unsubscribe from this group, send email to > algogeeks+unsubscr...@googlegroups.com<algogeeks%2bunsubscr...@googlegroups.com> > . > For more options, visit this group at > http://groups.google.com/group/algogeeks?hl=en. > -- You received this message because you are subscribed to the Google Groups "Algorithm Geeks" group. To post to this group, send email to algoge...@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en.