@coolfrog

in case of AB we asked to A know B after checking this we eliminate A n same
case go for CD den

A B          CD
   |             |
   A            D

         AD     Same approach
           |
           D (D will be celebrity)


On Fri, Sep 24, 2010 at 10:57 AM, kartheek muthyala
<kartheek0...@gmail.com>wrote:

> @coolfrog,
>
> What I meant by remained is
>
> Considering your case of A,B,C,D and B is the celebrity,
>
> The sequence is
>
> First A,B ask the question to A, then remained=B
> Then B,C ask the question to B, then remained=B
> Then B,D ask the question to B, then remained= B
> Then ask A,C,D whether they know B
> Then ask B whether they know A,C,D
>
> So, that's how I said 3(n-1) questions...
> Correct me if I am wrong
>
> On Thu, Sep 23, 2010 at 8:32 PM, coolfrog$ <
> dixit.coolfrog.div...@gmail.com> wrote:
>
>>
>> @kartheek
>> i am getting. this prudent approach....
>> but what is "add what remained to the remainder."
>> suppose u have A,B,C,D and B is celebrity ...
>>
>> if( A knows B)
>>   { A is not celb.
>>        if( B knows C){}
>>          else{ C is not celb.
>>                   if (C knows B )
>>                        {  if( D knows B)
>>                                   { D is not celb.
>>                                        only B remain... hence it  celeb...
>>                                           /* suppose if u have A,B,C,D,E
>> and B is celeb.
>>                                               then  again  if (E knows B)
>>                                                             {    E is not
>> celb....
>>                                                                   only B
>> remain... hence it  celeb...
>>                                                             }
>>                                           */
>>                                   }
>>                        }
>>               }
>>  }
>> look in every if condition  we are Asking Sequentially  to A
>> ,B,C,D,E.......
>> can these be  correct solution ....
>> correct me plz... if wrong......
>>  On Thu, Sep 23, 2010 at 12:56 AM, kartheek muthyala <
>> kartheek0...@gmail.com> wrote:
>>
>>>  Take 2 persons, suppose say A and B
>>> ask one of them the question about other
>>> if A Knows B, then A cannot be the celebrity,
>>> if A does not know B, then B cannot be the celebrity.
>>> add what remained to the remainder.
>>>
>>> repeat this process for the remaining n-1 until one or none remained.
>>>
>>> Then if it is none then there is no celebrity.
>>> If there is one ask the question whether this person is known by
>>> remaining n-1 and this person does n't know the remaining n-1. So a total of
>>> 3(n-1) questions is used to determine the celeb.
>>>
>>> Time complexity is O(n).
>>>
>>> Repeat this for the remaining n-1 persons, if the remainder contain one
>>> then
>>>
>>>
>>> On Wed, Sep 22, 2010 at 9:37 PM, Divesh Dixit <
>>> dixit.coolfrog.div...@gmail.com> wrote:
>>>
>>>> Among n people, a celebrity is defined as someone who is known to
>>>> everyone, but who knows no
>>>> one. Design and analyze to identify the celebrity, if one exists, by
>>>> asking only questions of the
>>>> following form: "Excuse me, do you know person x?" You will get a
>>>> binary answer for each such
>>>> question asked. Find the celebrity by asking only O(n) questions.
>>>>
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Thanks & Regards

Umesh kewat

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