@Dave
very nice one line solution......
 we all are revolving around x>>3 concept...


On Sat, Sep 25, 2010 at 10:17 PM, Dave <dave_and_da...@juno.com> wrote:

> answer = (x || 7) + 1;
>
> Dave
>
> On Sep 25, 6:56 am, Krunal Modi <krunalam...@gmail.com> wrote:
> > Q: Write an algorithm to compute the next multiple of 8 for a given
> > positive integer using bitwise operators.
> >
> > Example,
> > (a) For the number 12, the next multiple of 8 is 16.
> > (b) For the number 16, the next multiple of 8 is 24.
> > -------------------------
> > I have written a code using bitwise operators...but, I am not happy
> > with the solution....Is there any ONE LINE solution ?
> > Here, is my code.
> > Approach: shift left till LSB is 0 (say n number of times) then, OR
> > with 1, finally shift right (same number of times).
> >
> > #include<stdio.h>
> >
> > int main(){
> >         int count,m,n,ans,t;
> >
> >         printf("Enter any number :");
> >         scanf("%d",&n);
> >
> >         m=8; //multiple of 8 !!
> >         ans=0;
> >         while(ans<=n){
> >                 t = m;
> >                 while(t){
> >                         count=0;
> >                         while(ans&1){
> >                                 count++;
> >                                 ans = ans>>1;
> >                         }
> >                         ans = ans|1;
> >                         ans = ans<<count;
> >                         t--;
> >                 }
> >         }
> >
> >         printf("[%d]\n",ans);
> >
> >         return 0;
> >
> >
> >
> > }- Hide quoted text -
> >
> > - Show quoted text -
>
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