firstly evaluate all prefix forms..++a will become 6..then a++ will remain
6..a=7 because postfix form of a will make it so..hence the result
7+6+6=19..
On Sat, Nov 6, 2010 at 9:39 PM, Dave <dave_and_da...@juno.com> wrote:
> @Bipul21: This is nonstandard, so the results are compiler-dependent.
> It is improper to have more than one assignment to the same variable
> between synchronization points.
>
> Dave
>
> On Nov 6, 10:42 am, bipul21 <bipuljai...@gmail.com> wrote:
> > #include<stdio.h>
> > int main()
> > {
> > int a=5;
> > a=a+(a++)+(++a);
> > printf("%d",a);
> > return 0;}
> >
> > answer is 19 but how??
>
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