basically it depend upon the way the parameters arre called ...it varies
from one compiler to other....
On Sat, Nov 6, 2010 at 9:50 PM, Shalini Sah <shalinisah.luv4cod...@gmail.com
> wrote:
> firstly evaluate all prefix forms..++a will become 6..then a++ will remain
> 6..a=7 because postfix form of a will make it so..hence the result
> 7+6+6=19..
>
>
> On Sat, Nov 6, 2010 at 9:39 PM, Dave <dave_and_da...@juno.com> wrote:
>
>> @Bipul21: This is nonstandard, so the results are compiler-dependent.
>> It is improper to have more than one assignment to the same variable
>> between synchronization points.
>>
>> Dave
>>
>> On Nov 6, 10:42 am, bipul21 <bipuljai...@gmail.com> wrote:
>> > #include<stdio.h>
>> > int main()
>> > {
>> > int a=5;
>> > a=a+(a++)+(++a);
>> > printf("%d",a);
>> > return 0;}
>> >
>> > answer is 19 but how??
>>
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