@Coolfrog$: Don't forget the bitwise logical products. What is the bit
patterns in those hexadecimal constants? Work out the whole example
and you will see how it works. -- Dave

On Nov 21, 8:21 am, "coolfrog$" <dixit.coolfrog.div...@gmail.com>
wrote:
> @gene
> plz explain .. what is going on... by taking example..... i am unable to run
> a test case
> 1. x=0xAD (1010 1101)
>   2.  x<<1  ===>01011010
>          |
>       x>>1 ====>01010110
>               x  =    01011110
> how we will get
>  answer as ( 0101 1011).....??????
>
>
>
>
>
> On Sun, Nov 21, 2010 at 9:59 AM, Gene <gene.ress...@gmail.com> wrote:
> > if the input is in unsigned char x, then
>
> > x = ((x << 1) & 0xAA) | ((x >> 1) & 0x55)
> > x = ((x << 2) & 0xCC) | ((x >> 2) & 0x33)
>
> > On Nov 20, 10:41 pm, Divesh Dixit <dixit.coolfrog.div...@gmail.com>
> > wrote:
> > > assuming all are 8bit no.
> > > input = 0x46  (0100   0110)
> > >  output = 0x26 ( 0010  0110 )
> > > input = 0x75 (0111  0101)
> > > output = 0xFC (1110  1010 )
>
> > > Algorithm..???
>
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> --
> *Divesh*
> (¨`·.·´¨) Always
>   `·.¸(¨`·.·´¨ ) Keep
>   (¨`·.·´¨)¸.·´Smiling!
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