x=((x>>3)&(0x11)|(a<<3)& 0x88 |(a>>1)& 0x44 | (a<<1) && 0x22)

On Sun, Nov 21, 2010 at 11:11 PM, Dave <dave_and_da...@juno.com> wrote:

> @Coolfrog$: Don't forget the bitwise logical products. What is the bit
> patterns in those hexadecimal constants? Work out the whole example
> and you will see how it works. -- Dave
>
> On Nov 21, 8:21 am, "coolfrog$" <dixit.coolfrog.div...@gmail.com>
> wrote:
> > @gene
> > plz explain .. what is going on... by taking example..... i am unable to
> run
> > a test case
> > 1. x=0xAD (1010 1101)
> >   2.  x<<1  ===>01011010
> >          |
> >       x>>1 ====>01010110
> >               x  =    01011110
> > how we will get
> >  answer as ( 0101 1011).....??????
> >
> >
> >
> >
> >
> > On Sun, Nov 21, 2010 at 9:59 AM, Gene <gene.ress...@gmail.com> wrote:
> > > if the input is in unsigned char x, then
> >
> > > x = ((x << 1) & 0xAA) | ((x >> 1) & 0x55)
> > > x = ((x << 2) & 0xCC) | ((x >> 2) & 0x33)
> >
> > > On Nov 20, 10:41 pm, Divesh Dixit <dixit.coolfrog.div...@gmail.com>
> > > wrote:
> > > > assuming all are 8bit no.
> > > > input = 0x46  (0100   0110)
> > > >  output = 0x26 ( 0010  0110 )
> > > > input = 0x75 (0111  0101)
> > > > output = 0xFC (1110  1010 )
> >
> > > > Algorithm..???
> >
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-- 
DIPANKAR DUTTA
M-TECH,Computer Science & Engg.
E&C Dept,IIT ROORKEE
Uttarakhand , India – 247667
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