@anoop in fact, it always work even if there are repeated elements, because they don't change the decision. in detail, assume ii, ,jj, kk is one of the answers, then a[ii]+a[jj]=a[kk]. since the array is sorted, so a[ii-1]+a[jj] <= a[kk] and a[ii] + a[jj+1] >= a[kk]. so when you try the pair of 'ii-1' and 'jj', the next step must be calculate a[ii] + a[jj] as long as a[ii-1]+a[jj] is not equal to a[kk]. the same to the pair 'ii' and 'jj+1'. the algorithm is correct and in the whole procedure, repeated elements don't affect the decision. I'm sorry for my poor English. Thank You!
On Thu, Dec 2, 2010 at 12:14 PM, anoop chaurasiya < anoopchaurasi...@gmail.com> wrote: > sorry for the interruption,we can make it work even if the elements are > repeated, by removing the duplicacy in linear time(as the array is already > sorted) and taking a count of no. of duplicates in the seperate array. > > On Wed, Dec 1, 2010 at 9:37 PM, Senthilnathan Maadasamy < > senthilnathan.maadas...@gmail.com> wrote: > >> A small correction to the algorithm above. In Step 3, instead of finding >> *any* pair (a,b) such that a+b = x we need to find *all* such pairs. >> However the complexity remains the same. >> >> -- >> You received this message because you are subscribed to the Google Groups >> "Algorithm Geeks" group. >> To post to this group, send email to algoge...@googlegroups.com. >> To unsubscribe from this group, send email to >> algogeeks+unsubscr...@googlegroups.com<algogeeks%2bunsubscr...@googlegroups.com> >> . >> For more options, visit this group at >> http://groups.google.com/group/algogeeks?hl=en. >> > > > > -- > Anoop Chaurasiya > CSE (2008-2012) > NIT DGP > > -- > You received this message because you are subscribed to the Google Groups > "Algorithm Geeks" group. > To post to this group, send email to algoge...@googlegroups.com. > To unsubscribe from this group, send email to > algogeeks+unsubscr...@googlegroups.com<algogeeks%2bunsubscr...@googlegroups.com> > . > For more options, visit this group at > http://groups.google.com/group/algogeeks?hl=en. > -- You received this message because you are subscribed to the Google Groups "Algorithm Geeks" group. To post to this group, send email to algoge...@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en.
